(x-5)(x+2)=x^2+5x+6

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Solution for (x-5)(x+2)=x^2+5x+6 equation: 



(x-5)(x+2)=x^2+5x+6

We move all terms to the left:

(x-5)(x+2)-(x^2+5x+6)=0

We get rid of parentheses

-x^2+(x-5)(x+2)-5x-6=0

We multiply parentheses ..

-x^2+(+x^2+2x-5x-10)-5x-6=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+2x-5x-10)-5x-6=0

We get rid of parentheses

-1x^2+x^2+2x-5x-5x-10-6=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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